3925. Concatenate Array With Reverse
Description
You are given an integer array nums of length n.
Construct a new array ans of length 2 * n such that the first n elements are the same as nums, and the next n elements are the elements of nums in reverse order.
Formally, for 0 <= i <= n - 1:
ans[i] = nums[i]ans[i + n] = nums[n - i - 1]
Return an integer array ans.
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Example 1:
Input: nums = [1,2,3]
Output: [1,2,3,3,2,1]
Explanation:
The first n elements of ans are the same as nums.
For the next n = 3 elements, each element is taken from nums in reverse order:
ans[3] = nums[2] = 3ans[4] = nums[1] = 2ans[5] = nums[0] = 1
Thus, ans = [1, 2, 3, 3, 2, 1].
Example 2:
Input: nums = [1]
Output: [1,1]
Explanation:
The array remains the same when reversed. Thus, ans = [1, 1].
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Constraints:
1 <= nums.length <= 1001 <= nums[i] <= 100
Solutions
Solution 1
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