2408. Design SQL 🔒

Description

You are given two string arrays, names and columns, both of size n. The i^th table is represented by the name names[i] and contains columns[i] number of columns.

You need to implement a class that supports the following operations:

Insert a row in a specific table with an id assigned using an auto-increment method, where the id of the first inserted row is 1, and the id of each new row inserted into the same table is one greater than the id of the last inserted row, even if the last row was removed.
Remove a row from a specific table. Removing a row does not affect the id of the next inserted row.
Select a specific cell from any table and return its value.
Export all rows from any table in csv format.

Implement the SQL class:

SQL(String[] names, int[] columns)
- Creates the n tables.
bool ins(String name, String[] row)
- Inserts row into the table name and returns true.
- If row.length does not match the expected number of columns, or name is not a valid table, returns false without any insertion.
void rmv(String name, int rowId)
- Removes the row rowId from the table name.
- If name is not a valid table or there is no row with id rowId, no removal is performed.
String sel(String name, int rowId, int columnId)
- Returns the value of the cell at the specified rowId and columnId in the table name.
- If name is not a valid table, or the cell (rowId, columnId) is invalid, returns "<null>".
String[] exp(String name)
- Returns the rows present in the table name.
- If name is not a valid table, returns an empty array. Each row is represented as a string, with each cell value (including the row's id) separated by a ",".

Example 1:

Input:

["SQL","ins","sel","ins","exp","rmv","sel","exp"]
[[["one","two","three"],[2,3,1]],["two",["first","second","third"]],["two",1,3],["two",["fourth","fifth","sixth"]],["two"],["two",1],["two",2,2],["two"]]

Output:

[null,true,"third",true,["1,first,second,third","2,fourth,fifth,sixth"],null,"fifth",["2,fourth,fifth,sixth"]]

Explanation:

// Creates three tables.
SQL sql = new SQL(["one", "two", "three"], [2, 3, 1]);

// Adds a row to the table "two" with id 1. Returns True.
sql.ins("two", ["first", "second", "third"]);

// Returns the value "third" from the third column
// in the row with id 1 of the table "two".
sql.sel("two", 1, 3);

// Adds another row to the table "two" with id 2. Returns True.
sql.ins("two", ["fourth", "fifth", "sixth"]);

// Exports the rows of the table "two".
// Currently, the table has 2 rows with ids 1 and 2.
sql.exp("two");

// Removes the first row of the table "two". Note that the second row
// will still have the id 2.
sql.rmv("two", 1);

// Returns the value "fifth" from the second column
// in the row with id 2 of the table "two".
sql.sel("two", 2, 2);

// Exports the rows of the table "two".
// Currently, the table has 1 row with id 2.
sql.exp("two");

Example 2:

Input:

["SQL","ins","sel","rmv","sel","ins","ins"]
[[["one","two","three"],[2,3,1]],["two",["first","second","third"]],["two",1,3],["two",1],["two",1,2],["two",["fourth","fifth"]],["two",["fourth","fifth","sixth"]]]

Output:

[null,true,"third",null,"<null>",false,true]

Explanation:

// Creates three tables.
SQL sQL = new SQL(["one", "two", "three"], [2, 3, 1]); 

// Adds a row to the table "two" with id 1. Returns True. 
sQL.ins("two", ["first", "second", "third"]); 

// Returns the value "third" from the third column 
// in the row with id 1 of the table "two".
sQL.sel("two", 1, 3); 

// Removes the first row of the table "two".
sQL.rmv("two", 1); 

// Returns "<null>" as the cell with id 1 
// has been removed from table "two".
sQL.sel("two", 1, 2); 

// Returns False as number of columns are not correct.
sQL.ins("two", ["fourth", "fifth"]); 

// Adds a row to the table "two" with id 2. Returns True.
sQL.ins("two", ["fourth", "fifth", "sixth"]);

Constraints:

n == names.length == columns.length
1 <= n <= 10⁴
1 <= names[i].length, row[i].length, name.length <= 10
names[i], row[i], and name consist only of lowercase English letters.
1 <= columns[i] <= 10
1 <= row.length <= 10
All names[i] are distinct.
At most 2000 calls will be made to ins and rmv.
At most 10⁴ calls will be made to sel.
At most 500 calls will be made to exp.

Follow-up: Which approach would you choose if the table might become sparse due to many deletions, and why? Consider the impact on memory usage and performance.

Solutions

Solution 1: Hash Table

Create a hash table tables to store the mapping of table names to table data rows. Directly simulate the operations in the problem.

The time complexity of each operation is \(O(1)\), and the space complexity is \(O(n)\).

Python3JavaC++Go

class SQL:
    def __init__(self, names: List[str], columns: List[int]):
        self.tables = defaultdict(list)

    def insertRow(self, name: str, row: List[str]) -> None:
        self.tables[name].append(row)

    def deleteRow(self, name: str, rowId: int) -> None:
        pass

    def selectCell(self, name: str, rowId: int, columnId: int) -> str:
        return self.tables[name][rowId - 1][columnId - 1]


# Your SQL object will be instantiated and called as such:
# obj = SQL(names, columns)
# obj.insertRow(name,row)
# obj.deleteRow(name,rowId)
# param_3 = obj.selectCell(name,rowId,columnId)

class SQL {
    private Map<String, List<List<String>>> tables;

    public SQL(List<String> names, List<Integer> columns) {
        tables = new HashMap<>(names.size());
    }

    public void insertRow(String name, List<String> row) {
        tables.computeIfAbsent(name, k -> new ArrayList<>()).add(row);
    }

    public void deleteRow(String name, int rowId) {
    }

    public String selectCell(String name, int rowId, int columnId) {
        return tables.get(name).get(rowId - 1).get(columnId - 1);
    }
}

/**
 * Your SQL object will be instantiated and called as such:
 * SQL obj = new SQL(names, columns);
 * obj.insertRow(name,row);
 * obj.deleteRow(name,rowId);
 * String param_3 = obj.selectCell(name,rowId,columnId);
 */

class SQL {
public:
    unordered_map<string, vector<vector<string>>> tables;
    SQL(vector<string>& names, vector<int>& columns) {
    }

    void insertRow(string name, vector<string> row) {
        tables[name].push_back(row);
    }

    void deleteRow(string name, int rowId) {
    }

    string selectCell(string name, int rowId, int columnId) {
        return tables[name][rowId - 1][columnId - 1];
    }
};

/**
 * Your SQL object will be instantiated and called as such:
 * SQL* obj = new SQL(names, columns);
 * obj->insertRow(name,row);
 * obj->deleteRow(name,rowId);
 * string param_3 = obj->selectCell(name,rowId,columnId);
 */

type SQL struct {
    tables map[string][][]string
}

func Constructor(names []string, columns []int) SQL {
    return SQL{map[string][][]string{}}
}

func (this *SQL) InsertRow(name string, row []string) {
    this.tables[name] = append(this.tables[name], row)
}

func (this *SQL) DeleteRow(name string, rowId int) {

}

func (this *SQL) SelectCell(name string, rowId int, columnId int) string {
    return this.tables[name][rowId-1][columnId-1]
}

/**
 * Your SQL object will be instantiated and called as such:
 * obj := Constructor(names, columns);
 * obj.InsertRow(name,row);
 * obj.DeleteRow(name,rowId);
 * param_3 := obj.SelectCell(name,rowId,columnId);
 */

2408. Design SQL 🔒

Description

Solutions

Solution 1: Hash Table

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