2396. Strictly Palindromic Number

SourceBiweekly Contest 86 Q2DifficultyMediumRating1328

Description

An integer n is strictly palindromic if, for every base b between 2 and n - 2 (inclusive), the string representation of the integer n in base b is palindromic.

Given an integer n, return true if n is strictly palindromic and false otherwise.

A string is palindromic if it reads the same forward and backward.

Example 1:

Input: n = 9
Output: false
Explanation: In base 2: 9 = 1001 (base 2), which is palindromic.
In base 3: 9 = 100 (base 3), which is not palindromic.
Therefore, 9 is not strictly palindromic so we return false.
Note that in bases 4, 5, 6, and 7, n = 9 is also not palindromic.

Example 2:

Input: n = 4
Output: false
Explanation: We only consider base 2: 4 = 100 (base 2), which is not palindromic.
Therefore, we return false.

Constraints:

• 4 <= n <= 105

Solutions

Solution 1: Quick Thinking

When \(n = 4\), its binary representation is \(100\), which is not a palindrome;

When \(n \gt 4\), its \((n - 2)\)-ary representation is \(12\), which is not a palindrome.

Therefore, we can directly return false.

The time complexity is \(O(1)\), and the space complexity is \(O(1)\).

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class Solution:
    def isStrictlyPalindromic(self, n: int) -> bool:
        return False

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class Solution {
    public boolean isStrictlyPalindromic(int n) {
        return false;
    }
}

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class Solution {
public:
    bool isStrictlyPalindromic(int n) {
        return false;
    }
};

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func isStrictlyPalindromic(n int) bool {
    return false
}

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function isStrictlyPalindromic(n: number): boolean {
    return false;
}

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impl Solution {
    pub fn is_strictly_palindromic(n: i32) -> bool {
        false
    }
}

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bool isStrictlyPalindromic(int n) {
    return 0;
}

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